-q^2+55q+8750=0

Solution for -q^2+55q+8750=0 equation:

-q^2+55q+8750=0

We add all the numbers together, and all the variables

-1q^2+55q+8750=0

a = -1; b = 55; c = +8750;
Δ = b2-4ac
Δ = 552-4·(-1)·8750
Δ = 38025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{38025}=195$
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(55)-195}{2*-1}=\frac{-250}{-2}
=+125
$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(55)+195}{2*-1}=\frac{140}{-2}
=-70
$